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-5p^2+15p-2=0
a = -5; b = 15; c = -2;
Δ = b2-4ac
Δ = 152-4·(-5)·(-2)
Δ = 185
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{185}}{2*-5}=\frac{-15-\sqrt{185}}{-10} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{185}}{2*-5}=\frac{-15+\sqrt{185}}{-10} $
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